Question

Find two numbers such that one of the them exceed the other by 18 and their sum is 98

Answer 1

Answer:

Let the number be x

According to the question

The other number = (x - 18)

Now,

x + (x - 18) = 98

x + x - 18 = 98

2x = 98 + 18

2x = 116

x = 116/2

x = 58

The other number x-18

= 58 - 18

= 40

The numbers will be 58 and 40

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