Find two numbers such that one of them exceeds by other by 8and their sum is 80
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Let one number is X
Other number be X+8
Sum of the numbers is 80, so x+(x+8) = 80
2x+8=80
2x=80-8
2x=72
x=36
one number is 36
other number is x+8
=36+8=44
sum of 36 and 44 is 80.
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