Question

Find two numbers such that one of them exceeds The Other by 18 and their sum is 92

Answer 1

hiiii!!!!

here's ur answer...

let the two numbers be x and x + 18.

sum of the two numbers = 92

therefore x + x + 18 = 92

==> 2x + 18 = 92

==> 2x = 92 - 18

==> 2x = 74

==> x = 74/2

==> x = 37

hence, first number = x

= 37

second number = x + 18

= 55

VERIFICATION:-

sum of the numbers = 37 + 55

= 92

hence verified

hope this helps u frnd..!!

Answer 2

take 1 no as x
and the other as x+18
x+x+18=92
2x=92-18
2x=74
x=74÷2
x=37
one no. =37
the other no. is x+18=55

hope this helps