find two numbers such that,one of them is equal is 8 more than the other and their sum is equal to 64? please tell with steps
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Answered by
22
Let the smaller number be X
Then, the other number would be X+8
Their sum given, 64
That means, X+X+8 =64
2X+8=64
2X=56
X=28
Other number is X+8=28+8=36
Then, the other number would be X+8
Their sum given, 64
That means, X+X+8 =64
2X+8=64
2X=56
X=28
Other number is X+8=28+8=36
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Answered by
9
Hello !
n + ( n + 8 ) = 64
2n + 8 = 64
2n = 64 - 8 = 56
n = 56 ÷ 2 = 28
28 + 8 = 36
n + ( n + 8 ) = 64
2n + 8 = 64
2n = 64 - 8 = 56
n = 56 ÷ 2 = 28
28 + 8 = 36
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