Question

Find two numbers such that the sum of the first and the second is 142 and four times the first Exide the second by 138​

Answer 1

Let the first number be a

Second number = 142 - a

According to question,

4a = 142 -a + 138

=> 5a = 280

=> a = 56

First number= 56

Second number= 142 - 56 = 86

Answer 2

Answer:

Step-by-step explanation:

Let the numbers are x and y

Their sum x + y = 142

4x = y + 138

4x = ( 142 - x ) + 138

5x = 280

x = 56

Then y = 142 - x

y = 142 -56 = 86

The numbers are 56 and 86