Math, asked by paroshnee18, 1 year ago

pls help i will mark you as brainliest pls
Four bells toll at an interval of 8,12,15,18 seconds respectively.all the four begin to toll together,how many times wil they tol together in one hour excluding the one at the start?

Answers

Answered by fireleo112003
2

Answer:

Step-by-step explanation:

Hey mate here is your answer,

Given,

all 4 bells toll at 8,12,15,18 seconds respectively,

to find the answer you need to take out the LCM of the given numbers.

that is 120 sec=120/60 = 2 min

that means that they will toll after every 2  min.

Therefore answer will be 30.

they will toll 30 times in a hour.

Answered by siddhartharao77
5

Answer:

10 times

Step-by-step explanation:

Let us find the LCM of 8,12,15 and 18 = 2 * 2 * 2 * 3 * 3 * 5 = 360.

So, after 360 seconds i.e after 6 minutes four bells will together toll together.

So, in 1 hour that is in 60 minutes these four bell will together toll:

= 60/6

= 10 times

Hope it helps!

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