find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.
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The sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2. Let the first number be x and the second number be y. Hence, the first number is 25 and the second number is 14.
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