Question

Find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2​

Answer 1

Answer:

x=25

y=14

Step-by-step explanation:

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92      

⇒4x−7y=2        

Multiply the first equation by 2 , and subtract eqn (1) from eqn (2)  

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y= 182 / 13 = 14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x= 50 / 2 = 25