Question

Find two numbers such that the sum of two thrice the first and the second is 142 and four times the first excids the second by 138

Answer 1

let number is x and y
3x+y=142
4x-y =138
by solving elimination method
7x=280
x=280/7
x=40
3x+y=142
120+y=142
y=142-120
y =22
ANSWER
first number is 40
and second number is 22


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