Question

Find two numbers such that their mean proportion is 8 and third proportion is 64.

Answer 1

Solution-: 4 and 16
For number a and b mean proportion= √(ab).
√(4*16)= 8

For number a and b third proportion=( b^2)/a.
( 16^2)/4.
=64.

Answer 2

Answer:

Two numbers are 4 and 16.

Step-by-step explanation:

Given :  Mean proportion is 8 and third proportion is 64.

To find : The two numbers?

Solution :

Let the numbers be a and b.

For number a and b mean proportion= $\sqrt{ab}$

According to the question,

$\sqrt{ab}=8$  ........[1]

For number a and b third proportion= $\frac{b^2}{a}$

According to the question,

$\frac{b^2}{a}=64$   ........[2]

Solving [1] and [2],

a=4 and b=16

Therefore, Two numbers are 4 and 16.