Question

Find two numbers such that their sum is 42 and difference is 16​

Answer 1

The sum of two numbers is 42 and their difference is 16. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 42. In other words, x plus y equals 42 and can be written as equation A:

x + y = 42

The difference between x and y is 16. In other words, x minus y equals 16 and can be written as equation B:

x - y = 16

Now solve equation B for x to get the revised equation B:

x - y = 16

x = 16 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 42

16 + y + y = 42

16 + 2y = 42

2y = 26

y = 13

Now we know y is 13. Which means that we can substitute y for 13 in equation A and solve for x:

x + y = 42

x + 13 = 42

X = 29

Summary: The sum of two numbers is 42 and their difference is 16. What are the two numbers? Answer: 29 and 13 as proven here:

Sum: 29 + 13 = 42

Difference: 29 - 13 = 16

Answer 2

Step-by-step explanation:

Let a & b are two numbers

a+ b = 42

A-B = 16

Add these equations

2a = 58

a = 29

So b = 42 - a

b = 42-29

b = 13