Math, asked by sgauravarun007, 3 months ago

Find two numbers whose difference, sum and product are in the ratio
4:6:25.​

Answers

Answered by abhi569
11

Answer:

25 and 5

Step-by-step explanation:

Let the numbers are x and y. As the ratio is 4:6:25, let difference, sum and product be 4a, 6a, and 25a.

=> x - y = 4a & x + y = 6a

Adding both, 2x = 10a => x = 5a

Subtract (x-y) from (x+y), y = a

As stated, product = 25a

=> xy = 25a

=> (5a)(a) = 25a {from above}

=> a² = 5a

=> a = 5

Hence, numbers are :

x = 5a = 5(5) = 25

y = a = 5

Answered by Anonymous
2

Answer:

25

5

Step-by-step explanation:

xy = 25a

(5a)(a) = 25a  

a² = 5a

a = 5

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