Find two numbers whose product is 42.Ten times the greater one may exceed 200 by asuch as 5 times the less fell short of 20?(Solve the Question via algebra)
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Find two numbers whose product is 42.Ten times the greater one may exceed 200 by asuch as 5 times the less fell short of 20?
Find the numbers =?
42 can be product of = 1 × 42 , 2 × 21 , 3 × 14 , 6 × 7
For first 1 × 42 here greater number is 42 , so
42× 10 = 420 that is greater than 200 by
420 - 200 = 220
And 5 times of smaller = 1 × 5 = 5
that is falls short of 20 = 20 - 5 = 15
So,
We can see that
15 ≠ 220
here greater number is 21 , so 21 × 10 = 210
That is greater than 200 by
210 - 200 = 10
And
5 times of smaller number = 2 × 5 = 10
That is falls short of 20 = 20 - 10 = 10
Hence
10 = 10
So our two numbers that gives As product of 42 , and satisfied our given two condition is = 2 and 21
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