Question

Find two numbers whose product is 42.Ten times the greater one may exceed 200 by asuch as 5 times the less fell short of 20?(Solve the Question via algebra)

Answer 1

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Find two numbers whose product is 42.Ten times the greater one may exceed 200 by asuch as 5 times the less fell short of 20?

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Find the numbers =?

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42 can be product of = 1 × 42 , 2 × 21 , 3 × 14 , 6 × 7

For first 1 × 42 here greater number is 42 , so

42× 10 = 420 that is greater than 200 by

420 - 200 = 220

And 5 times of smaller = 1 × 5 = 5

that is falls short of 20 = 20 - 5 = 15

So,

We can see that

15 ≠ 220

$\large{ \sf \underline{ \blue{Now \: we \: check \: for \: 2 × 21 : - }}}$

here greater number is 21 , so 21 × 10 = 210

That is greater than 200 by

210 - 200 = 10

And

5 times of smaller number = 2 × 5 = 10

That is falls short of 20 = 20 - 10 = 10

Hence

10 = 10

So our two numbers that gives As product of 42 , and satisfied our given two condition is = 2 and 21

Answer 2

Answer:

Step-by-step explanation: