Question

find two numbers whose sum is 24 and difference is 8

Answer 1

let the two no be 2x
and 2x+x=24
2x/x=12
x+x=24-2
=22
2x-x=8
x-x=8/2
4
Try it might help

Answer 2

Let numbers be x and y,
By first condition,
x+y=24 ----(eq. 1)
By second condition,
x-y=8 ---(eq 2)
Adding equation 1 and 2
x+y=24
+ x-y=8
------------------
2x =16
x=16÷2
x=8
Now substituting x=8 in equation 1
x+y=24
8+y=24
y=24-8
y=16.
x=8;y=16.
Hope it helps you!