Question

find two numbers whose sum is 26 and difference is 2 using one variable

Answer 1

Answer:

12 and 14

Step-by-step explanation:

Let the first number be x.

Now,

According to question, difference is 2,

=> second number is x+2.

Now

x + x + 2 = 26

2x + 2 = 26

2x = 24

x = 12

Thus, x+2=14

Answer 2

Answer:

$\underline{ \Large \mathtt{Given: }}$

$\large two \: numbers \: = 26$

$\large difference \: of \: 2$

$\underline{ \Large\mathtt{To \: find : }}$

$\large two \: number \: having\: sum \: of \: 26$

$\underline{ \Large {\mathtt {Solution : }}}$

$Lets \: the \: first \: digit \: be \: = \: x \\ \: and \: secound \: digit \: be \: = y$

$also, \: both \: having \: difference \: of \: 2.$

So, according to the question,,

We will minus 2 from 26 = 24

x + y + 2 = 24

2y + 2 = 24

y + 2 = 24/2

y + 2 = 12

And, taking x = 12

taking 2 + y = 12 + 2 = 14

$\large \mathtt{so, \: when \: we \: take \: x = 12} \\ \mathtt{ and \: y = 14} \\ \mathtt{hence \: x + y = 26} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \green{ \mathtt{ 12 + 14 = 26}}$

$\mathtt{and \: both \: have \: the \: difference \: of \: 2}$