find two numbers whose sum is 27 and product is 182
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Answered by
14
Hi friend,
Here is your answer,
_____________________________________________________________
Let the numbers be x and y.
x+y = 27 -----------------(i)
xy = 182 -----------------(ii)
From (i) ,
x = 27- y
Put it in (ii)
(27- y)y = 182
27y - y² = 182
y²- 27y +182 = 0
y² - 14y - 13y + 182 = 0
y(y-14)+13(y-14) = 0
(y -13)(y - 14) = 0
y -13 = 0 y - 14 = 0
y = 13 y = 14
Required numbers are :- 13 and 14
_____________________________________________________________
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Here is your answer,
_____________________________________________________________
Let the numbers be x and y.
x+y = 27 -----------------(i)
xy = 182 -----------------(ii)
From (i) ,
x = 27- y
Put it in (ii)
(27- y)y = 182
27y - y² = 182
y²- 27y +182 = 0
y² - 14y - 13y + 182 = 0
y(y-14)+13(y-14) = 0
(y -13)(y - 14) = 0
y -13 = 0 y - 14 = 0
y = 13 y = 14
Required numbers are :- 13 and 14
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
Anonymous:
pls mark as brainliest
Answered by
7
Hello..
x+y = 27
xy=182
x= 182/y
182/y+y =27
182+y^2=27
y^2-27y+182=0
y^2-14y-13y+182=0
y(y-14)*-13(y-14)=0
(y-14)(y-13)=0
y=14,y=13
when y=14,
x+14=27
⇒x=13
13 and 14
x+y = 27
xy=182
x= 182/y
182/y+y =27
182+y^2=27
y^2-27y+182=0
y^2-14y-13y+182=0
y(y-14)*-13(y-14)=0
(y-14)(y-13)=0
y=14,y=13
when y=14,
x+14=27
⇒x=13
13 and 14
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