Question

Find two numbers whose sum is 48 and product is 432. quadratic equation

Answer 1

Hey mate thank for the question
Let the numbers =x and y
ATP=>x+y=48
y=48-x
x*y=432
Putting the value of y
x*(48-x)=432
-x^2+48x=432
0=x^2-48+432
0=x^2-(36+12)x+432
0=x^2-36x-12x+432
0=x(x-36)-12(x-36)
0=(x-36)(x-12)
x=36,12
y=12,36

Answer 2

Hey !!! ^_^

Here is your answer

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Let the no. be x

Whose sum is 48 and other no. be (48 - x)

And their products is 432

( x ) ( 48 - x ) = 432

48x - x² = 432

x² - 48x + 432 = 0

x² - 36x - 12x + 432 = 0

x( x - 36) - 12( x - 36) = 0

x - 12 = 0......or x - 36 = 0

x = 12 ......or.....x = 36


If the value of x is 12

then the two no. are 12 and 48 - 12 = 36

And if the Value of x is 36

then the two no. are 36 and 48 - 36 = 12


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