Find two numbers whose sum is 6 and product is 18.
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Step-by-step explanation:
xy=9
x=9/y
x+y=6
9/y+y=6
y(9/y+y)=6×y
y²+9-6y=6y-6y
y²-6y+9=0
(y-3)(y+3)=0
So y can either be -3 or 3 here. Let's try -3 first.
If y=-3, then -3x=9.
-3x/-3=9/-3
x=-3
-3+(-3)=-6, not 6.
Alternatively, if y=-3, then x+(-3)=6
x-3+3=6+3
x=9
9×-3=-27, not 6.
So y must equal 3.
If y=3, 3x=9
3x/3=9/3
x=3
3+3=6
So the two numbers are 3 and 3.
138 views · Answer requested by Achuth L Sarith

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