Find two numbers whose sum is 64 and difference is 4
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Let the numbers are x and y. Given
x + y = 64 ……. ( 1 )
x - y = 4 ……. ( 2 )
Adding ( 1) and ( 2 ), we get 2x = 68 =>
x = 34
Substitute x = 34 in ( 2), we get
34 - y = 4 => y = 34 - 4 = 30
So, the two numbers are 30 and 34.
Answered by
1
Answer:
the two number whose sum is 64 and difference is 4 is
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