Question

Find two numbers whose sum is 78 and product is 1512

Answer 1

Answer:

one number is x.

second will be (78-x)...

According to question,

x(78-x)= 1512

78x-x2= 1512

x2-78x+1512=0

x2-42x-36x+1512=0

x(x-42)-36(x-42)=0

x=42,x=36

Answer 2

Answer:

42 and 36

Step-by-step explanation:

sum of two number=78

x+y=78 y=78-x

xy=1512

then, x(78-x)=1512

x^2-78x+1512=0

x^2-42x-36x+1512=0

x(x-42) -36(x-42) =0

(x-42) (x-36) =0

I) x-42=0

x=42

2) x-36=0

x=36

then the two numbers are 42 and 36.