Find two numbers whose sum is27 and product is 182
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Answered by
24
Let the numbers be x and y
So, x + y = 27 and xy = 182
According to the question,
x = 27 - y
So, xy = 182
( 27 - y )y = 182
27y - y² = 182
y² - 27y + 182 = 0
y² - 13y - 14y + 182 = 0
y( y - 13 ) + 14( y - 13 ) = 0
( y - 13 )( y + 14 ) = 0
y = 13 or - 14
The numbers are 13 or -14
So, x + y = 27 and xy = 182
According to the question,
x = 27 - y
So, xy = 182
( 27 - y )y = 182
27y - y² = 182
y² - 27y + 182 = 0
y² - 13y - 14y + 182 = 0
y( y - 13 ) + 14( y - 13 ) = 0
( y - 13 )( y + 14 ) = 0
y = 13 or - 14
The numbers are 13 or -14
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Answered by
7
let 1st no, be x
sum of 2 no. is 27
x + second no.= 27
secobd no. = 27- x
now, the product = 182
x * ( 27 - x ) = 182
27x - x^2 = 182
x^2 - 27x +182 = 0
x^2 -13x-14x +182 = 0
x ( x-13 ) - 14 (x -13 ) =0
(x-13) - ( x -14 ) =0
x -13 =0 or x-14 = 0
sa, x may be 13 or 14
so two numbers are 13 or 14 .
hope this is helpful. please mark as brainlist .....
sum of 2 no. is 27
x + second no.= 27
secobd no. = 27- x
now, the product = 182
x * ( 27 - x ) = 182
27x - x^2 = 182
x^2 - 27x +182 = 0
x^2 -13x-14x +182 = 0
x ( x-13 ) - 14 (x -13 ) =0
(x-13) - ( x -14 ) =0
x -13 =0 or x-14 = 0
sa, x may be 13 or 14
so two numbers are 13 or 14 .
hope this is helpful. please mark as brainlist .....
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