Question

find two numbers whose sume is 24 and difference is 8 in substitution

Answer 1

Let two numbers be x and y
I'm which x is greater
given,
x+y=24
x-y=8
Now, substitutuon method,
x=24-y
putting balue of x in second equation,
(24-y)-y=8
24-y-y=8
24-2y=8
2y=24-8
y=16/2
y=8;
and,
x=24-y
x=24-8
x=16;

Answer 2

Heya user ,
Here is your answer !!

__________

Let the two numbers be x and y .

So , x + y = 24
So , y = 24 - x .

Now , acc. to the question ,

x - y = 8
=> x - ( 24 - x ) = 8
=> x - 24 + x = 8 [ substituting the value of y ]
=> 2x = 24 + 8
=> 2x = 32
=> x = 16 . [ Answer ] .

so , y = 24 - x
=> y = 24 - 16
=> y = 8 . [ Answer ] .

__________

Hope it helps !!