Math, asked by thehalfgoldengamer, 4 months ago

Find two numbers with a sum of 65. Twice the smaller number is 10 more than the larger number.

Answers

Answered by 5honey
1

Answer:

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Step-by-step explanation:

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Answered by Arnold1234
0

Step-by-step explanation:

Let,

Smaller number be= x

Larger number= (x × 2)+10

= 2x+10

According to the question,

(2x+10)+x=65

or,(2x+x)=65-10

or,3x=55

or,x=55÷3

=18.33

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