Question

Find two other zeroes if
p(x) = 2x^3 + x^2 -7x-6, having one of its zeroes as 2.​

Answer 1

Step-by-step explanation:

Given ,

x=−3 is zero of given polynomial

x+3=0

Now ,

x+3p(x)=x−32x2−3x−2

 

 

  x−32x3+3x−11x−6=2x2−3x−2

 2x2−4x+x−2=0

 2x(x−2)+1(x−2)=0

 (2x+1)(x−2)=0

When ,

  2x+1=0

 x=−21

When,

  x−2=0

 x=2

Hence others two zeroes are 2,−21 .