Find two pairs of solutions for a and b, such that, a^b +b^a=100, where a and b are natural numbers
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Hi ,
Let a = 2 , b = 6
a^b + b^a = 2^6 + 6²
= 64 + 36
= 100
Therefore ,
a = 2 , b = 6
I hope this helps you.
:)
Let a = 2 , b = 6
a^b + b^a = 2^6 + 6²
= 64 + 36
= 100
Therefore ,
a = 2 , b = 6
I hope this helps you.
:)
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