Question

find two parallel sides of a trapezium which have area of 126 msqaure and altitude is 10 dm and one of parallel side is longer than other by 8m

Answer 1

let 1st parallel side be x
then, 2nd = 8 plus x

now, area of parallelogram =
$1 \div 2 \times (x + x +8) \times 100$
126= 1/2*
$2x + 8 \times 100$
126 *2 =2x plus 8* 100
126 *2/100= 2x plus 8
126 /50= 2x plus 8
63/25 =2x plus 8
now , solve it next