Question

Find two parts of 34 such as that [4/7]th of one part is equal to [2/5]th of the other?

A) 16,18
B) 14,20
C)15,19
D) None of these

please give me answer with full explanation...​

Answer 1

answer is b

let first part x and 2nd part 34 - X

let first part x and 2nd part 34 - Xa/c to question,

let first part x and 2nd part 34 - Xa/c to question,4/7 (x) = (34 - x )(2/5)

let first part x and 2nd part 34 - Xa/c to question,4/7 (x) = (34 - x )(2/5)4x/7 + 2x/5 = 34 x 2/5 = 68/5

let first part x and 2nd part 34 - Xa/c to question,4/7 (x) = (34 - x )(2/5)4x/7 + 2x/5 = 34 x 2/5 = 68/534x/35 = 68/5

let first part x and 2nd part 34 - Xa/c to question,4/7 (x) = (34 - x )(2/5)4x/7 + 2x/5 = 34 x 2/5 = 68/534x/35 = 68/5x= 14

Answer 2

Step-by-step explanation:

let first part x second part 34-x

acc. to question

(4/7) * x = (2/5)* (34-x)

4x/7 = 68/5 - 2x/5

4x/7 + 2x/5 = 68/5

(20x + 14x)/35 = 68/5

34x/35 = 68/5

x = 68/5 * 35/34 = 14

so first part 14 second part 34-14 = 20