Question

Find two positive consecutive odd numbers the sum of whose squares is 74

Answer 1

Answer:

5 and 7

Step-by-step explanation:

let the numbers be a , a+2

a²+(a+2)²=74

a²+a²+4a+4

2a²+4a-70=0

a²+2a-35=0

(a²+7a) - (5a-35)

a(a+7) -5(a-7)

(a-5) (a-7)

a= 5 and 7

Answer 2

here is ur ans...hope this helps if so mark as brainliest