Question

Find two solutions for each of the following equations:
(i) 4r + 3y = 12
(ii) 2x + 5y = 0
(iii) 3y + 4 = 0​

Answer 1

Answer:

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Answer 2

Answer:

2x−5y=0⇒x=

2

5

y

at y=2x=5

aty=4x=10

so (5, 2) (10, 4) are solutions