Question

Find usin identity(2y+1)2​

Answer 1

${(2y + 1)}^{2} \\ \\ {(2y)}^{2} + {(1)}^{2} + 2 \times 2y \times 1 \\ \\ 4 {y}^{2} + 1 + 4y$

Answer 2

Answer:

4y² + 1 + 4y

solutions.

(2y + 1)²

(2y)^2 + (1) + 2 × 2y × 1

4y² + 1 + 4y

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silentlover45.❤️

Answer 3

Answer:

4y² + 1 + 4y

solutions.

(2y + 1)²

(2y)^2 + (1) + 2 × 2y × 1

4y² + 1 + 4y

Thank ❤️

hope it helps you.

silentlover45.❤️