Question

Find using identities
$(\frac{2x}{3} + \frac{3x}{2} ) ^{2}$
​

Answer 1

Answer:

$(\frac{2x}{3} + \frac{3x}{2} ) ^{2} \\ = \frac{169 {x}^{2} }{36}$

Step-by-step explanation:

$(\frac{2x}{3} + \frac{3x}{2} ) ^{2} \\ = ( {\frac{2x}{3})}^{2} + 2 \times \frac{2x}{3} \times \frac{3x}{2} + ( {\frac{3x}{2})}^{2} \\ = \frac{ {4 {x}^{2}}}{9} + 2 {x}^{2} + \frac{ {9x}^{2} }{4} \\ = \frac{16 {x}^{2} + 72 {x}^{2} + 81 {x}^{2} }{36} \\ = \frac{169 {x}^{2} }{36}$

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