Question

Find using identity: (1/2x-1/5y) (1/2x-1/5y)

Answer 1

Answer:

(1/2x-1/5y)(1/2x-1/5y)

(1/2x-1/5y)^2

using identity (a+b)^2=a^2+b^2+2*a*b

(1/2x)^2 + (1/5y)^2 + 2*1/2x*1/5y

1/4x^2 + 1/25y^2 + 1/5xy

Answer 2

Answer:

(1/2x-1/5y) whole square

or it can be

(1/2x) square × 2(1/2x×-1/5y) ×(1/5y)square