Question

Find using identity
a)103×104
B)5.1×5.2

Answer 1

) 738×103
By using distributive property;
We get,
= 738(100+3)
= 738×100+738×3
= 73800+2214
= 76014
(b) 854 × 102
By using distributive property, we get,
= 854 × (100+2)
= 854×100+854×2
= 85400+1708
= 87108
(c) 258 × 1008
By using distributive property, we get,
= 258 × (1000+8)
= 258×1000+258×8
= 258000+2064
= 260064
(d) 1005×168
By using distributive property, we get,
= (1000+5) ×168
= 1000×168+5×168
= 168000+840
= 168840

Answer 2

Heya ##

103×104
It iz in the form (x+a)(x+b)
(100+3)(100+4)
=x^2+(a+b)x+ab
=100^2+(3+4)100+3×4
=10000+700+12
=10712..

5.1×5.2


It iz in the form of (x+a)(x+b)
(5+0.1)(5+0.2)
=x^2+(a+b)x+ab
=5^2+(0.1+0.2)5+0.1×0.2
=25+1.5+0.02
=26.52...