find value of A (0°<A°<90°) if cos 63° sec (90-A) = 1. it's urgent please answer. don't spam. spams will be Reported.
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cos 63° sec(90°-θ)=1
⇒cos 63° cosec θ=1
⇒ cos 63°=sin θ
⇒ cos 63°=cos (90°-θ)
⇒ 63°=90°-θ
⇒θ=27°
Therefore, the value of the variable is 27.
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