Question

find value of 'a' and 'b' so that x⁴+x³+8x+ax-b is divisible by x²+1​

Answer 1

Answer:

14523

Step-by-step explanation:

Answer 2

Answer:

a=9 , b=19

Step-by-step explanation:

x²-1 is a factor

∴ x = ±1

$1^{4}$ + 1³ +8(1) +a(1) - b = 0  ===============>1

$(-1)^{4}$ + (-1)³ +a(-1) -b =0  ===============>2

equate 1&2

∴ 1+1+8+a-b = 1-1-a-b

solving we get a=9

from 1

1+1+8+9-b = 0

b = 19