find value of cot2^=1/sin2^
fahad2674:
fibd theta
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tell ur perfect question plzzz
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Answer:
Step-by-step explanation:
Cot2^=1/sin2^
Cos2^/Sin^2 - 1/Sin2^
Cos2^-1/Sin2^
-Sin2^/Sin2^ (Cos2^-1= Sin2^)
-1
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