The sum of ages of father and his son is 60. After 14 years, father's age will be three times the age of the son. Find their present ages
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let the age of son be x years
and let the age of father be y years
a/q
x+y=60....... (I)
after 14 years age of son will be x+14
and age of father will be y+14
again a/q
y+14=3(x+14)
y+14= 3x+42
3x-y = 14-42=-28 .......(ii)
from I and ii we get
x+y =60........I
3x-y=-28
by adding we get
4x= 32
x=8
therefore age of son =8 years
and age of father = 52 years
and let the age of father be y years
a/q
x+y=60....... (I)
after 14 years age of son will be x+14
and age of father will be y+14
again a/q
y+14=3(x+14)
y+14= 3x+42
3x-y = 14-42=-28 .......(ii)
from I and ii we get
x+y =60........I
3x-y=-28
by adding we get
4x= 32
x=8
therefore age of son =8 years
and age of father = 52 years
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