Question

find value of k, -4 is zero of polynomial x2 -x-(2k+2)

Answer 1

Answer:

9

Step-by-step explanation:

Originally Answered: For what value of k(-4) is a zero of the polynomial x square-x-(2k+2)? Hope it will help you! This happened because if something is called the zero of a polynomial then it simply means that if we replace the variable of the equation(like in most cases) by that something then we get 0. So k = 9.

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Answer 2

$k=9$, is the value of k in the polynomial.

Step by step calculation

Given data:

The polynomial given: $x^{2} -x-(2k+2)$

To find:

We need to find the value of k in the given polynomial.

Formula to be used:

$f(-4)=x^{2} -x-(2k+2)$

Solution:

Given the polynomial: $x^{2} -x-(2k+2)$

we must substitute $k=-4$ in the above polynomial using the equation:

$f(-4)=x^{2} -x-(2k+2)$$=0$

0$=-4^{2} +4-2k-2$

0$=16+4-2k-2$

0$=18-2k$

$18=2k$

$k=9$

Therefore for  the polynomial $x^{2} -x-(2k+2)$, the value of k is $9$

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