find value of k for quadratic equation 2x²+kx+3 so that they have 2 equal root
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Verification:
2x² ± 2√6x + 3 = 0
(√2x)² ± 2(√2)(√3)x + (√3)² = 0
(√2x ± 3)² = 0
x = ±(√3/√2).
2x² ± 2√6x + 3 = 0
(√2x)² ± 2(√2)(√3)x + (√3)² = 0
(√2x ± 3)² = 0
x = ±(√3/√2).
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