find value of k for which a root of quadratic equation
x²-2(1+3k)x + 7(3+2k)=0 is 7
Answers
Answered by
7
on replacing value of x with 7 we get
7²-2(1+3k)7 + 7(3+2k)=0
49- 14- 42k+ 21+ 14k =0
70-14-28k=0
56=28k
k=56/28=2
k=2
7²-2(1+3k)7 + 7(3+2k)=0
49- 14- 42k+ 21+ 14k =0
70-14-28k=0
56=28k
k=56/28=2
k=2
isranikhushi156:
thnkuu i was just getting wrong in the calculation..
you're welcome
Answered by
3
Answer:
Step-by-step explanation:
Attachments:
Similar questions