Question

Moist nitrogen at a pressure of 700 mm of Hg and temperature 27 degree celsius is found to occupy a volume of 100 cm cube find the volume of dry Nitrogen gas at 57.8 (aqueous tension at 27 degree is 15 mm of Hg)

Answer 1

As temp is same so
P1 v1 = p2 v2
V2 = p1 v1 ÷ p2
V2 = 700 × 100 ÷ 15
V2 = 4666.66 dm3

Answer 2

The temperature is same. 
So, It will be:-- 
P1 v1 = p2 v2 
V2 = p1 v1 ÷ p2
V2 = 700 × 100 ÷ 15
V2 = 4666.66 dm3

tHANKS