Find value of k for which eqn 2x2+kx+8=0 have equal roots
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2
Answer:
There are two possible values for k.
k = 8 and k = -8
Step-by-step explanation:
The quadratic has equal roots
=> the discrimant is equal to zero
=> k² - 4×2×8 = 0
=> k² = 64
=> k = ±8
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