Question

find value of k, if 2x-3 is a factor of 2x square-9x cube+x+k​

Answer 1

Answer:

Step-by-step explanation:

Given : 2x - 3 is a factor of 2x^2 -9x^3 +X + k

Zero of 2x-3 is 3/2

P(3/2) = 2*(3/2)^2 - 9(3/2)^3+3/2+k = 0

9/2-81/8+3/2+k = 0

(36-81+12)/8+k = 0

(48-81)/8+k = 0

33/8+k = 0

k = 0*8/33

k= 0