find value of k, if (k+1)square -2(k+4)x+2k=0 have equal roots.
Ramlayaksingh3:
what is the answer given in the book?
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Answered by
1
k+1=0
k=-1
2(k+4)x+2k=0
2(-1+4)x+2(-1)=0
3x+2=0-2
3x+2=-2
3x=2-2
3x=0
x=0/3=0
k=-1
2(k+4)x+2k=0
2(-1+4)x+2(-1)=0
3x+2=0-2
3x+2=-2
3x=2-2
3x=0
x=0/3=0
i am not sure about the answer
why
k+1 is included in polynomial
leave it thanks for answering
wlc
Answered by
10
mark as brainlist pls
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Thank you for answering bro
Hm
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