Question

Find value of k if
kx+3y=k-3 and
12x+ky=k​

Answer 1

1. kx+3y=k-3

kx-k=-3-3y

k(x-1)=-3(1+y)

k=-3(1+y)/(x-1)

2. 12x+ky=k

ky-k=-12x

k(y-1)=12x

k=12x/y-1