find value of k if pair of linear eqation 4x+6y-1=0and 2x+ky-7=0 represent parallel lines
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The two given lines are
4x + 6y - 1 = 0 ...(i)
2x + ky - 7 = 0 ...(ii)
If the two lines (i) and (ii) be parallel to each other,
{coefficient of x of (i)}/{coefficient of x of (ii)}
= {coefficient of y of (i)}/{coefficient of y of (ii)}
=> 4/2 = 6/k
=> 2 = 6/k
=> 2k = 6
=> k = 6/2
=> k = 3
Therefore, the value of k is 3.
#MarkAsBrainliest
The two given lines are
4x + 6y - 1 = 0 ...(i)
2x + ky - 7 = 0 ...(ii)
If the two lines (i) and (ii) be parallel to each other,
{coefficient of x of (i)}/{coefficient of x of (ii)}
= {coefficient of y of (i)}/{coefficient of y of (ii)}
=> 4/2 = 6/k
=> 2 = 6/k
=> 2k = 6
=> k = 6/2
=> k = 3
Therefore, the value of k is 3.
#MarkAsBrainliest
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