Question

Find value of k if the triangle formed by A(8, -10), B(7, -3), C(0, k) is right angled at B.

Answer 1

Answer:

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Answer 2

Answer:

k = - 4

Step-by-step explanation:

A(8, - 10), B(7, - 3)

$m_{AB}$ = $\frac{-3+10}{7-8}$ = - 7

y + 3 = - 7(x - 7)

y = - 7x + 46 is an equation of line passing points A and B

BC ⊥ AB , then slope of BC is opposite reciprocal to (- 7)

y + 3 = $\frac{1}{7}$ (x - 7)

y = $\frac{1}{7}$ x - 4 is an equation of line passing point B and perpendicular to AB

Coordinates of C is (0, - 4) ⇒ k = - 4