Question

find value of K of the following pair of eq have infinitely many sol.2x-3y=7. (K+1) x+(1-2k)y=(5k-4)

Answer 1

Hi !

2x-3y=7

2x - 3y - 7 = 0
a₁ = 2 , b₁ = -3 , c₁ = -7

(K+1) x+ (1- 2 k)y = (5 k-4)
(K+1) x+ (1- 2 k)y - (5 k-4) = 0


a₁ = k+1 , b₁ = 1-2k , c₁ = -(5k + 4)




If the equations have infinitely may solutions :-
a₁/a₂ = b₁/b₂ = c₁/c₂

2/k+1 = -3/1-2k = -7/-(5k+4)

2/k+1 = -3/1-2k

cross multiplying :-
-3(k+1) = 2(1-2k)

-3k -3 = 2 - 4k

-3k+4k = 2+3

k = 5

If k = 5 , we get can infinite solutions for the equations given .

Answer 2

Hi !

2x-3y=7

2x - 3y - 7 = 0

a₁ = 2 , b₁ = -3 , c₁ = -7

(K+1) x+ (1- 2 k)y = (5 k-4)

(K+1) x+ (1- 2 k)y - (5 k-4) = 0

a₁ = k+1 , b₁ = 1-2k , c₁ = -(5k + 4)

If the equations have infinitely may solutions :-

a₁/a₂ = b₁/b₂ = c₁/c₂

2/k+1 = -3/1-2k = -7/-(5k+4)

2/k+1 = -3/1-2k

cross multiplying :-

-3(k+1) = 2(1-2k)

-3k -3 = 2 - 4k

-3k+4k = 2+3

k = 5

If k = 5 , we get can infinite solutions for the equations given

Read more on Brainly.in - https://brainly.in/question/1278263#readmore