find value of k so that Kx(3-4x)+9=0 has equal roots
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Step-by-step explanation:
Kx(3-4x) +9 =0
3kx -4kx^2+9=0
has equal roots then
b^2-4ac=0
(3k)^2 - 4 × (-4k) × 9 =0
9k^2 + 144k =0
9k(k+16) =0
k = 0 or -16
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