Question

find value of n for 4 (32 n + 1) = 49​

Answer 1

Answer: this is an eg not the answer 1.3(c). Clearly, rn > 1 for each n, so that from (b), rn+1 - rn and rn - rn-I have

opposite signs and

1

Irn+l - rnl < 41rn - rn-II·

Since r2 > 1 = rl, it follows that rl < r3 < r2. Suppose as an induction

hypothesis that

rl < r3 < ... < r2m-1 < r2m < ... < r2.

Then 0 < r2m - r2m+1 < r2m - r2m-1 and 0 < r2m+2 - r2m+1 < r2m - r2m+J.

so that r2m-1 < r2m+1 < r2m+2 < r2m. Let k, 1 be any positive integers. Then, for

m > k, I, r2k+1 < r2m-1 < r2m < r21.

l.3(d). Leta be the least upper bound (i.e., the smallest number at least as great as

all) of the numbers in the set {rl, r3, r5, ... , r2k+l, ... }. Then r2m-1 ::::: a ::::: r2m

Step-by-step explanation:

Answer 2

4(32n+1)=49

32n+1=49÷4

32n=49÷4-1

N=(49/4-1)find ans and divide by 3

Thus the final answer will be 3.75

Hope it helps you